Distance = Rate * Time Problem?

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A man has 3.25 hours in which to give some friends a tour of the surrounding countryside. How farm from the house can the tour extend if the speed on the trip out is 25km/h and the speed of the return trip is 40km/h?

This is a distance = rate*time problem and I am very bad with word problems..can someone please explain to me on how to do this step by step?

Distance = Rate * Time Problem?

let x be the distance they have gone from his house

we have

x / 25 + x / 40 = 3.25(3.25 is the total time in which they go there and return the house)

=> x = 50 km

Distance = Rate * Time Problem?

The thing to understand first is that distance on the way out and on the way back have to equal the same number. Now, we set up two different equations for the two different rates that result in distance as the answer. For example:

Distance = rate*time

Let's set distance equal to D.

D = rate*time

For the way out: 25km/h is the rate.

D = 25*time

In order to figure out time, we have to take the total time and subtract one way. We can set the way BACK as x. Thus, the way out would equal 3.25-x. We place that in the equation.

D = 25*(3.25-x)

There's the first equation.

Second, we do the same for the way back.

D is still equal to distance because the distance out and the distance back should be the same.

D = rate*time

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Distance = Rate * Time Problem?

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